宠物店做网站的论文宁波seo优化公司

题目描述

题解思路

深度优先遍历二叉树，遍历的同时记录路径，直到遍历到叶节点，若路径和为targetSum则添加到结果集中

题解代码

func pathSum(root *TreeNode, targetSum int) [][]int {var res = make([][]int, 0)path := make([]int, 0, 1)var sum func(root *TreeNode, targetSum int)sum = func (root *TreeNode, targetSum int) {if root == nil {return}targetSum -= root.Valpath = append(path, root.Val)defer func() { path = path[:len(path)-1] }()if root.Left == nil && root.Right == nil && targetSum == 0 {res = append(res, append([]int{}, path...))return}sum(root.Left, targetSum)sum(root.Right, targetSum)}sum(root, targetSum)return res
}