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Unity的Random.Range介绍

有两个重载:

        如果参数存在至少一个浮点数那么将会触发public static  float Range(float minInclusive, float maxInclusive); 返回一个范围内的浮点数(包含首尾)

        如果参数都是整形则触发public static  int Range(int minInclusive, int maxExclusive) 返回一个整形(包含首但不包含尾);

 /// <summary>/// 在[start,end]整数数组中获取count数量的随机不重复数据(首位都包含)/// 例如[-1,100]拿5个不重复随机数可能拿到0,77,2,55,11/// </summary>/// <param name="start"></param>/// <param name="end"></param>/// <param name="count"></param>/// <returns></returns>/// <exception cref="ArgumentException"></exception>private int[] GetRandomArray(int start, int end, int count){if (start >= end){throw new ArgumentException("Start must be less than end.");}int legalCount = end - start + 1;if (legalCount < count||count==0){throw new ArgumentException("The count is greater than the number of available values.");}// 使用数组存储可用数字int[] availableNumbers = new int[legalCount];for (int i = 0; i < legalCount; i++){availableNumbers[i] = start + i;}int[] numbers = new int[count];//  洗牌算法for (int i = 0; i < count; i++){// 在每次迭代中，从 i 到 legalCount 范围随机选择一个索引int tempIndex = UnityEngine.Random.Range(i, legalCount);//0 1// 将随机选到的数字存入结果数组numbers[i] = availableNumbers[tempIndex];// 将选中的数字移到已选区域（位置 i）,下次循环会来到后一个位置availableNumbers[tempIndex] = availableNumbers[i];}return numbers;}